Tính S(n) = 1 + 1/3 + 1/5 + … + 1/(2n + 1)

#include<stdio.h>
#include<conio.h>

int main()
{
	int i, n;
	float S;
	S = 0;
	do
	{
		printf("\nNhap n: ");
		scanf("%d", &n);
		if(n < 1)
		{
			printf("\nN phai lon hon hoac bang 1. Xin nhap lai !");
		}
	}while(n < 1);

	for(i = 0; i < n; i++)
	{
		S = S + 1.0 / ((2 * i) + 1);
	}
	printf("\nTong la: %f", S);

	getch();
	return 0;
}